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5w^2+30w-80=0
a = 5; b = 30; c = -80;
Δ = b2-4ac
Δ = 302-4·5·(-80)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-50}{2*5}=\frac{-80}{10} =-8 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+50}{2*5}=\frac{20}{10} =2 $
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